2x^2-52x+240=0

Solution for 2x^2-52x+240=0 equation:

2x^2-52x+240=0

a = 2; b = -52; c = +240;
Δ = b2-4ac
Δ = -522-4·2·240
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-28}{2*2}=\frac{24}{4}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+28}{2*2}=\frac{80}{4}
=20
$